w^2+9w+3=0

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Solution for w^2+9w+3=0 equation: 



w^2+9w+3=0

a = 1; b = 9; c = +3;
Δ = b2-4ac
Δ = 92-4·1·3
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{69}}{2*1}=\frac{-9-\sqrt{69}}{2}
$


$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{69}}{2*1}=\frac{-9+\sqrt{69}}{2}
$

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